This is the circuit diagram of a simple 100 watt inverter using IC CD4047 and MOSFET
IRF540 which i uesd for my final year project. The circuit is simple low cost and can be even assembled on veroboard or breadboard beofre finally put in the casing.
When pin 10 is high Q1 conducts and current flows through the upper half of the transformer primary which accounts for the positive half of the output AC voltage. When pin 11 is high Q2 conducts and current flows through the lower half of the transformer primary in opposite direction and it accounts for the negative half of the output AC voltage.
Take Note of:
- B1 can be a 12V/ 6Ah lead acid battery.
- Q1 and Q2 must be fitted to a proper heat sink.
- T1 can be a 9-0-9 V primary, 230V secondary, 150VA transformer .
- Do not expect much from this circuit. The is very
simple one suitable for low grade applications.